SOLUTION: the perimete of a rectangle is 640m.twice the width is 40cm more than the length.find the dimensions of the rectangle.

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Question 879923: the perimete of a rectangle is 640m.twice the width is 40cm more than the length.find the dimensions of the rectangle.
Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39618) About Me  (Show Source):
You can put this solution on YOUR website!
w=L+40 and 2w+2L=640.
Two equations in two unknowns.

L=140, w=180

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!

the perimete of a rectangle is 640m.twice the width is 40cm more than the length.find the dimensions of the rectangle.


Width:  highlight_green%28highlight_green%28120%29%29 cm

Length: highlight_green%28highlight_green%28200%29%29 cm

You can do the check!! 



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