SOLUTION: solve -3sin^2(theta)+3cos^2(theta)=0

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Question 879919: solve -3sin^2(theta)+3cos^2(theta)=0
Answer by lwsshak3(11628) About Me  (Show Source):
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solve -3sin^2(theta)+3cos^2(theta)=0
-3sin%5E2%28x%29%2B3cos%5E2%28x%29=0
-3%28sin%5E2%28x%29-cos%5E2%28x%29%29=0
(sin^2(x)-cos^2(x)=0
sin^2(x)-1+sin^2(x)=0
2sin^(x)=1
sin^2(x)=1/2
sin(x)=±√(1/2)=±√2/2
x=π/4, 3π/4, 5π/4, 7π/4