SOLUTION: The third and fourth terms of a sequence are 101 and 83. If the first differences are a constant, find the first 5 terms in the sequence?

Algebra ->  Sequences-and-series -> SOLUTION: The third and fourth terms of a sequence are 101 and 83. If the first differences are a constant, find the first 5 terms in the sequence?       Log On


   

Question 879729: The third and fourth terms of a sequence are 101 and 83. If the first differences are a constant, find the first 5 terms in the sequence?
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
a%5Bn%5D+=+a%5B1%5D+%2B+%28n-1%29d
a%5B3%5D+=+a%5B1%5D+%2B+%282%29d+=+101
a%5B4%5D+=+a%5B1%5D+%2B+%283%29d+=+83 SUBTRACT EQs
-d = 18, d = -18 and a[1] = 137 a%5B1%5D+%2B+%282%29%28-18%29+=+101
{137, 119, 101, 83, 65,...}