SOLUTION: for real number x and y ,x^2+(y-4)^2=0 then value of x+y ?

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Question 879670: for real number x and y ,x^2+(y-4)^2=0 then value of x+y ?
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
x%5E2%2B%28y-4%29%5E2=0
There is only one real solution when both terms on the left hand side equal zero.
x=0
y-4=0
y=4
So then,
x%2By=4