Hi
Population: mean = 509, sd = 112
*Note: 
P(x ≥ 574.6)= 1 - P( z ≤ 65.6/112)= 1 - P(z ≤ .5857) = 1-.7210 = .2790 0r 27.9% chance
For the normal distribution: Below: z = 0, z = ± 1, z= ±2 , z= ±3 are plotted.
Area under the standard normal curve to the left of the particular z is P(z)
Note: z = 0 (x value: the mean) 50% of the area under the curve is to the left and 50% to the right
