SOLUTION: how do i solve the inequalitly 3 (2x-7) <5 (x+2)?

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Question 879576: how do i solve the inequalitly 3 (2x-7) <5 (x+2)?
Found 2 solutions by jim_thompson5910, lwsshak3:
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!

3%282x-7%29%3C5%28x%2B2%29 Start with the given inequality.


6x-21%3C5x%2B10 Distribute.


6x%3C5x%2B10%2B21 Add 21 to both sides.


6x-5x%3C10%2B21 Subtract 5x from both sides.


x%3C10%2B21 Combine like terms on the left side.


x%3C31 Combine like terms on the right side.


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Answer:

So the solution is x%3C31

Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
solve the inequalitly
3 (2x-7) <5 (x+2)
6x-21<5x+10
x>31
or
(31, ∞)