Question 879539: Jan is five years older than Leann. Three years ago, the sum of their ages was 35. Find the ages of each.
HELP!!! Answer by lwsshak3(11628) (Show Source):
You can put this solution on YOUR website! Jan is five years older than Leann. Three years ago, the sum of their ages was 35. Find the ages of each.
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let x=Leann's present age
x+5=Jan's present age
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3 yrs ago:
x-3=Leann's age
x+5-3=x+2=Jan's age
x-3+x+2=35
2x=36
x=18
x+5=23
Leann's present age=18
Jan's present age=23
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