SOLUTION: Thank you for taking my question. I believe it uses combinations and is a bit tricky:
The possibility that a basketball player will make a given free throw is 3/5. To find the p
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-> SOLUTION: Thank you for taking my question. I believe it uses combinations and is a bit tricky:
The possibility that a basketball player will make a given free throw is 3/5. To find the p
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Question 879525: Thank you for taking my question. I believe it uses combinations and is a bit tricky:
The possibility that a basketball player will make a given free throw is 3/5. To find the probability that the player makes exactly 9 out of his next 10 free throws, evaluate the term 10C9 (3/5)^9(2/5)^1 in the expansion of (3/5 + 2/5)^10 Answer by ewatrrr(24785) (Show Source):
You can put this solution on YOUR website! Previously Posted
Using
p and q are the probabilities of success and failure respectively.
In this case p = 3/5 and q = 2/5, n = 10
P(x = 9) = 10C9(3/5)^9(2/5)^1 = 10(3/5)^9(2/5)^1 = .0403 0r 4.03% chance
