SOLUTION: What is the length of the shortest side of a triangle that has vertices at (0,-6), (1,-2), and (-7,0)?
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Question 879483
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What is the length of the shortest side of a triangle that has vertices at (0,-6), (1,-2), and (-7,0)?
Answer by
ewatrrr(24785)
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(0,-6),
(1,-2) L = sqrt(1 + 16) D =
(-7,0) L = sqrt(64 + 4)
(0, -6) L = sqrt(49+36)