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Question 879452: of the two numbers,4 times the first is equal to 6 times the other and the sum of 3 times the first and 6 times the second is 105.the first number is
Answer by ankor@dixie-net.com(22740)   (Show Source):
You can put this solution on YOUR website! of the two numbers,
a & b
4 times the first is equal to 6 times the other
4a = 6b
or
4a - 6b = 0
:
and the sum of 3 times the first and 6 times the second is 105.
3a + 6b = 105
4a - 6b = 0
--------------------adding the two equations eliminates b, finda
7a = 105
a = 105/7
a = 15 is the first number
;
:
Check this, 4(15) = 6b
60 = 6b
b = 60/6
b = 10
3(15) + 6(10) = 105
45 + 60 = 105
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