SOLUTION: Identify the vertex, focus, and Directrix of the graph of this parabola: (x-1)^2 = (1/4)(y+2)

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Question 879415: Identify the vertex, focus, and Directrix of the graph of this parabola:
(x-1)^2 = (1/4)(y+2)
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
(x-1)^2 = (1/4)(y+2) Opening Upward along x = 1 y+=+4%28x-1%29%5E2+-2
C(1,-2), 4p = 1/4, p = 1/16, F(1, -1 15/16), Directrix is y = -2 1/16)

 

Hi

Need to Know...............................................................

Standard Form of an Equation of a Circle is %28x-h%29%5E2+%2B+%28y-k%29%5E2+=+r%5E2 

Standard Form of an Equation of an Ellipse is %28x-h%29%5E2%2Fa%5E2+%2B+%28y-k%29%5E2%2Fb%5E2+=+1+ 

Standard Form of an Equation of an Hyperbola opening up and down is:%28y-k%29%5E2%2Fb%5E2+-+%28x-h%29%5E2%2Fa%5E2+=+1 

Standard Form of an Equation of an Hyperbola opening right and  left is:%28x-h%29%5E2%2Fa%5E2+-+%28y-k%29%5E2%2Fb%5E2+=+1 

the vertex form of a Parabola opening up(a>0) or down(a<0), y=a%28x-h%29%5E2+%2Bk

 the vertex form of a Parabola opening right(a>0) or left(a<0), x=a%28y-k%29%5E2+%2Bh