Question 87924: I need help with a question that says: solve each of the following for x
*1/8=4^(6x+2)
*(1/4)^x=256
*log10x=4 Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! solve each of the following for x
*1/8=4^(6x+2)
2^-3 = 2^(2(6x+2))
-3 = 12x+4
12x = -7
x = -7/12
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*(1/4)^x=256
2^-2x = 2^8
-2x = 8
x = -4
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*log10x=4
Question: Does this mean log(10x) or log(base 10)x ?
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Cheers,
Stan H.
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