SOLUTION: At noon a train leaves Bridgton heading east at 90 mi/h to cogsville, 450 mi away. At 12:15 P.M. a train leaves Cogsville heading west to Bridgton at 100 mi/h. At what time will

Algebra ->  Customizable Word Problem Solvers  -> Travel -> SOLUTION: At noon a train leaves Bridgton heading east at 90 mi/h to cogsville, 450 mi away. At 12:15 P.M. a train leaves Cogsville heading west to Bridgton at 100 mi/h. At what time will      Log On

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Question 87921This question is from textbook
: At noon a train leaves Bridgton heading east at 90 mi/h to cogsville, 450 mi away. At 12:15 P.M. a train leaves Cogsville heading west to Bridgton at 100 mi/h. At what time will they pass each other? This question is from textbook

Answer by checkley75(3666) About Me  (Show Source):
You can put this solution on YOUR website!
90T+100(T-.25)=450
90T+100T-25=450
190T=450+25
190T=475
T=475/190
T=2.5 HOURS THEY WILL MEET.
PROOF
90*2.5+100*2.25=450
225+225=450
450=450