SOLUTION: I do not know where to even start with this problem. Trying to find two linear equations. The Wing House sells both regular and the jumbo size orders of buffalo chicken wings. Thr

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: I do not know where to even start with this problem. Trying to find two linear equations. The Wing House sells both regular and the jumbo size orders of buffalo chicken wings. Thr      Log On


   



Question 879197: I do not know where to even start with this problem. Trying to find two linear equations.
The Wing House sells both regular and the jumbo size orders of buffalo chicken wings. Three regular orders and five jumbo orders cost $67. Four regular and four jumbo orders cost $64. Find the cost of one regular and jumbo order of wings?

Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 
2 equations, 2 unknowns
3r + 5j = 67
4r + 4j = 64
3r + 5j = 67
r + j = 16 (times - 3, ADD the two EQ)
2j = 19
j = 19/2 = $9.50 and r = $6.50



First let A=%28matrix%282%2C2%2C3%2C5%2C4%2C4%29%29. This is the matrix formed by the coefficients of the given system of equations.


Take note that the right hand values of the system are 67 and 64 which are highlighted here:
system%283%2Ax%2B5%2Ay=highlight%2867%29%2C4%2Ax%2B4%2Ay=highlight%2864%29%29



These values are important as they will be used to replace the columns of the matrix A.




Now let's calculate the the determinant of the matrix A to get abs%28A%29=%283%29%284%29-%285%29%284%29=-8. Remember that the determinant of the 2x2 matrix A=%28matrix%282%2C2%2Ca%2Cb%2Cc%2Cd%29%29 is abs%28A%29=ad-bc. If you need help with calculating the determinant of any two by two matrices, then check out this solver.



Notation note: abs%28A%29 denotes the determinant of the matrix A.



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Now replace the first column of A (that corresponds to the variable 'x') with the values that form the right hand side of the system of equations. We will denote this new matrix A%5Bx%5D (since we're replacing the 'x' column so to speak).


A%5Bx%5D=%28matrix%282%2C2%2Chighlight%2867%29%2C5%2Chighlight%2864%29%2C4%29%29



Now compute the determinant of A%5Bx%5D to get abs%28A%5Bx%5D%29=%2867%29%284%29-%285%29%2864%29=-52. Once again, remember that the determinant of the 2x2 matrix A=%28matrix%282%2C2%2Ca%2Cb%2Cc%2Cd%29%29 is abs%28A%29=ad-bc



To find the first solution, simply divide the determinant of A%5Bx%5D by the determinant of A to get: x=%28abs%28A%5Bx%5D%29%29%2F%28abs%28A%29%29=%28-52%29%2F%28-8%29=13%2F2



So the first solution is x=13%2F2




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We'll follow the same basic idea to find the other solution. Let's reset by letting A=%28matrix%282%2C2%2C3%2C5%2C4%2C4%29%29 again (this is the coefficient matrix).




Now replace the second column of A (that corresponds to the variable 'y') with the values that form the right hand side of the system of equations. We will denote this new matrix A%5By%5D (since we're replacing the 'y' column in a way).


A%5Bx%5D=%28matrix%282%2C2%2C3%2Chighlight%2867%29%2C4%2Chighlight%2864%29%29%29



Now compute the determinant of A%5By%5D to get abs%28A%5By%5D%29=%283%29%2864%29-%2867%29%284%29=-76.



To find the second solution, divide the determinant of A%5By%5D by the determinant of A to get: y=%28abs%28A%5By%5D%29%29%2F%28abs%28A%29%29=%28-76%29%2F%28-8%29=19%2F2



So the second solution is y=19%2F2




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Final Answer:




So the solutions are x=13%2F2 and y=19%2F2 giving the ordered pair (13/2, 19/2)




Once again, Cramer's Rule is dependent on determinants. Take a look at this 2x2 Determinant Solver if you need more practice with determinants.