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Question 879109: sum of three consecutive numbers is 333. what is the sum of the last two numbers?
Answer by JulietG(1812)   (Show Source):
You can put this solution on YOUR website! A + B + C = 333
B = A-1
C = A-2 (because they're consecutive)
Substitute the known values of B and C into the first equation.
A + (A-1) + (A-2) = 333
Add
3A -3 = 333
Add 3 to each side
3A = 336
Divide each side by 3
A = 112
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If A is 112, then B is 111, and C is 110
The consecutive numbers are:
110,111,112
What is the sum of the last two?
111 + 112 = ?
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