SOLUTION: The directions say to solve the equation for x. -4+log9(2x)=-5 That log is supposed to have a base of 9 if that clears anything up. Could I please have detailed instructions

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: The directions say to solve the equation for x. -4+log9(2x)=-5 That log is supposed to have a base of 9 if that clears anything up. Could I please have detailed instructions       Log On


   

Question 879051: The directions say to solve the equation for x.
-4+log9(2x)=-5
That log is supposed to have a base of 9 if that clears anything up. Could I please have detailed instructions on how to solve it? I have a final tomorrow and I totally forgot how to solve this one. I tried to solve it and I have the answer because they are in the back of packet I received, but I need to know how to do it.
Thank you for your time.
Found 3 solutions by lwsshak3, josgarithmetic, MathTherapy:
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
solve the equation for x.
-4+log9(2x)=-5
log9(2x)=-1
convert to exponential form: (base(9) raised to log of the number(-1)=number(2x)
9^-1=2x
2x=1/9
x=1/18

Answer by josgarithmetic(39620) About Me  (Show Source):
You can put this solution on YOUR website!
-4%2Blog%289%2C2x%29=5

Add +4 to both sides;
change to exponential form;

9%5E9=2x, .....
How would you prefer to find 9%5E9? This would be about a nine-digit number.
highlight%28x=%281%2F2%299%5E9%29

highlight%28x=193710244.5%29
(a software-program number calculator was used)

Answer by MathTherapy(10553) About Me  (Show Source):
You can put this solution on YOUR website!

The directions say to solve the equation for x.
-4+log9(2x)=-5
That log is supposed to have a base of 9 if that clears anything up. Could I please have detailed instructions on how to solve it? I have a final tomorrow and I totally forgot how to solve this one. I tried to solve it and I have the answer because they are in the back of packet I received, but I need to know how to do it.
Thank you for your time.


-+4+%2B+log+%289%2C+2x%29+=+-+5

log+%289%2C+2x%29+=+-+5+%2B+4

log+%289%2C+2x%29+=+-+1

2x+=+9%5E-1

2x+=+1%2F9

18x = 1 ------ Cross-multiplying

highlight_green%28highlight_green%28x+=+1%2F18%29%29

You can do the check!! 



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