Question 879009: Write the equation of a hyperbola with vertices (3, -1) and (3, -9) and co-vertices (-6. -5) and (12, -5). Answer by lwsshak3(11628) (Show Source):
You can put this solution on YOUR website! Write the equation of a hyperbola with vertices (3, -1) and (3, -9) and co-vertices (-6. -5) and (12, -5).
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Given hyperbola has a vertical transverse axis:
Its standard form of equation: , (h,k)=coordinates of center
For given hyperbola:
y-coordinate of center=-5 (midpoint of -1 and -9 on the vertical transverse axis)
x-coordinate of center=3 (midpoint of -6 and 12 on the conjugate axis)
center: (3,-5)
length of vertical transverse axis=8(-1 to -9)=2a
a=4
a^2=16
length of conjugate axis=18(-6 to 12)=2b
b=9
b^2=81
equation:
(