SOLUTION: Elsa drove to the mountains last weekend. There was heavy traffic on the way there, and the trip took 8 hours. When she drove home, there was no traffic and the trip took 6 hours.

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Question 878872: Elsa drove to the mountains last weekend. There was heavy traffic on the way there, and the trip took 8 hours. When she drove home, there was no traffic and the trip took 6 hours. If her average rate was 16 mph faster on the trip home, how far away does Elsa live from the mountains?
Found 2 solutions by lwsshak3, josmiceli:
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
Elsa drove to the mountains last weekend. There was heavy traffic on the way there, and the trip took 8 hours. When she drove home, there was no traffic and the trip took 6 hours. If her average rate was 16 mph faster on the trip home, how far away does Elsa live from the mountains?
***
let x=rate of speed on the way to the mountain
x+16=rate of speed on the way home
distance=travel time*rate of speed
..
8x=6(x+16)
8x=6x+96
2x=96
x=48
distance=8*48=384
how far away does Elsa live from the mountains? 384 miles

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +r%5B1%5D+ = her ave rate going to mountains in mi/hr
Let +r%5B2%5D+ = her ave rate driving back in mi/hr
Let +d+ = the one-way distance to mountains
---------------
(1) +r%5B2%5D+=+r%5B1%5D+%2B+16+
(2) +r%5B1%5D+=+d+%2F+8+
(3) +r%5B2%5D+=+d+%2F+6+
-----------------
Substitute (2) and (3) into (1)
(1) +d%2F6+=+d%2F8+%2B+16+
Multiply both sides by +24+
(1) +4d+=+3d+%2B+16%2A24+
(1) +d+=+16%2A24+
(1) +d+=+16%2A24+
(1) +d+=+384+
----------------
(2) +r%5B1%5D+=+384+%2F+8+
(2) +r%5B1%5D+=+48+ mi/hr
and
(1) +r%5B2%5D+=+384+%2F+6+
(1) +r%5B2%5D+=+64+ mi/hr
Her ave rate going to mountains was 48 mi/hr
Her ave rate driving back was 64 mi/hr
-----------------------
check:
(1) +r%5B2%5D+=+r%5B1%5D+%2B+16+
(1) +64+=+48+%2B+16+
(1) +64+=+64+
OK