SOLUTION: How do I find the focus of the parabola x-m=-2((y+4)^2)=3?

 

Hi, Previously Posted

x-3=-2((y+4)^2)=3 ??? too many = signs

Anyhow: 4p = -1/2, p = -1/8  Parabola Opens left(-2 < 0) along line of symmetry: y = -4

Need to know the Vertex point..going to guess V(3,-4) ⇒ focus is F(2 7/8, -4)

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the vertex form of a Parabola opening right(a>0) or left(a<0), 

 where(h,k) is the vertex and  y = k  is the Line of Symmetry

The standard form is , 0r a = 1/4p, where  the focus is (h +p,k )  With Directrix x = (k-p)