SOLUTION: A valuable collection of coins contained old nickels, dimes, quarters and pennies. The face value of the pennies was $6.00. There were five times as many quarters as dimes and fif

Algebra ->  Percentage-and-ratio-word-problems -> SOLUTION: A valuable collection of coins contained old nickels, dimes, quarters and pennies. The face value of the pennies was $6.00. There were five times as many quarters as dimes and fif      Log On


   



Question 878759: A valuable collection of coins contained old nickels, dimes, quarters and pennies. The face value of the pennies was $6.00. There were five times as many quarters as dimes and fifteen less than twice as many nickels as quarters. If the face value of the entire collection was $40.40. How many of each kind of the coin was there?
Answer by lwsshak3(11628) About Me  (Show Source):
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A valuable collection of coins contained old nickels, dimes, quarters and pennies. The face value of the pennies was $6.00. There were five times as many quarters as dimes and fifteen less than twice as many nickels as quarters. If the face value of the entire collection was $40.40. How many of each kind of the coin was there?
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let x=number of dimes
5x=number of quarters
2*5x-15=10x-15=number of nickels
.10x+.25*5x+.05(10x-15)+6.00=40.40
.10x+1.25x+.50x-.75+6.00=40.40
1.85x=35.15
x=19
5x=95
10x-15=175
..
number of dimes=19
number of quarters=95
number of nickels=175
number ofpennies=600