SOLUTION: x^2 + 19x + 92 = whole square of an integer when x is integer
find x
Attempted-
let a be the integer
x^2+19x+92-a^2=0
Discriminant>=0
361-4(92-a^2)>=0
4a^2>=7
a^2>=4/7
a<=
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Quadratic Equations and Parabolas
-> SOLUTION: x^2 + 19x + 92 = whole square of an integer when x is integer
find x
Attempted-
let a be the integer
x^2+19x+92-a^2=0
Discriminant>=0
361-4(92-a^2)>=0
4a^2>=7
a^2>=4/7
a<=
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Question 878715: x^2 + 19x + 92 = whole square of an integer when x is integer
find x
Attempted-
let a be the integer
x^2+19x+92-a^2=0
Discriminant>=0
361-4(92-a^2)>=0
4a^2>=7
a^2>=4/7
a<=-sqrt(7)/4 and a>=sqrt(7)/4
but a is integer
therefore a<=-2 or a>=2 Answer by josgarithmetic(39620) (Show Source):
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