SOLUTION: Graph the following systems of inequalities . Find the coordinates of any vertices formed. x + y ≤ 16 3x + 6y ≥ 60 x ≥ 0 y ≥ 0 Can you please hel

Algebra ->  Test -> SOLUTION: Graph the following systems of inequalities . Find the coordinates of any vertices formed. x + y ≤ 16 3x + 6y ≥ 60 x ≥ 0 y ≥ 0 Can you please hel      Log On


   



Question 878687: Graph the following systems of inequalities . Find the coordinates of any vertices formed.
x + y ≤ 16
3x + 6y ≥ 60
x ≥ 0
y ≥ 0
Can you please help me ? Thanks so much in advance:)

Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
system%28x%3E=0%2Cy%3E=0%29 just means the first quadrant, including the positive x- and y-axes.

x%2By%3C=16 means the line represented by x%2By=16 plus all the points to one side of that line.
Which side? The one with the origin, (0,0),
because substituting system%28x=0%2Cy=0%29 into x%2By%3C=16
makes it true: 0%2B0=0%3C16 .

3x%2B6y%3E=60 means the line represented by 3x%2B6y%3E=60<--->x%2B2y%3E=20 plus all the points to one side of that line.
Which side? The one without the origin, (0,0),
because substituting system%28x=0%2Cy=0%29 into 3x%2B6y%3E=60
makes it not true: 3%2A0%2B6%2A0=0%2B0=0%3C60 .

How can we graph the lines represented by
x%2By=16 and 3x%2B6y=60<--->x%2B2y=20 ?
These particular linear equations are easy to graph by finding their x- and y-intercepts.
For x%2By=16 :
system%28x=0%2Cx%2By=16%29-->system%28x=0%2Cy=16%29 gives us point (0,16).
system%28y=0%2Cx%2By=16%29-->system%28x=16%2Cy=0%29 gives us point (16,0).
Those two points allow us to graph the line x%2By=16 :

For 3x%2B6y=60<--->x%2B2y=20 :
system%28x=0%2Cx%2B2y=20%29-->system%28x=0%2Cy=10%29 gives us point (0,10).
system%28y=0%2Cx%2B2y=20%29-->system%28x=20%2Cy=0%29 gives us point (20,0).
Those two points allow us to graph the line x%2B2y=20 :


The region represented by system%28x%3E=0%2Cy%3E=0%2Cx%2By%3C=16%2C3x%2B6y%3E=60%29
is shown below as the triangle ABC.