SOLUTION: The length of a rectangle is 4 more than twice its width. If the width is represented by w, find the perimeter of the rectangle in terms of w.

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Question 878666: The length of a rectangle is 4 more than twice its width. If the width is represented by w, find the perimeter of the rectangle in terms of w.
Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39620) About Me  (Show Source):
You can put this solution on YOUR website!
You can generalize further and say, the length is k more than m times its width; find perimeter.

L=mw%2Bk and if p is perimeter, either known or unknown,p=2w%2B2L.
Substituting for L gives....
p=2w%2B2%28mw%2Bk%29
highlight%28p=2w%2B2mw%2B2k%29.

Your given description used k=4 and m=2.

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!

The length of a rectangle is 4 more than twice its width. If the width is represented by w, find the perimeter of the rectangle in terms of w. 


Perimeter, in terms of w: highlight_green%28highlight_green%286w+%2B+8%29%29