SOLUTION: If you have a rectangular rug whose perimeter is 26 feet and the length is three feet more than the width, what are the dimensions of the rug? (P=2w+2l)

Algebra ->  Customizable Word Problem Solvers  -> Geometry -> SOLUTION: If you have a rectangular rug whose perimeter is 26 feet and the length is three feet more than the width, what are the dimensions of the rug? (P=2w+2l)      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 878419: If you have a rectangular rug whose perimeter is 26 feet and the length is three feet more than the width, what are the dimensions of the rug? (P=2w+2l)
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
Not like P=2w+2l because it is not visually understood without extended effort. Call the length, L.

You have some general situation, L=w+d and 2w+2L=P for positive real numbers d, P; and the unknown variables are L and w.

2w%2B2%28w%2Bd%29=P, and you already have assigned d=3 and P=26.
2w%2B2w%2B2d=P
4w=P-2d
highlight%28w=%28P-2d%29%2F4%29
-
Use the formula given for L:
L=w%2Bd
L=%28P-2d%29%2F4%2Bd
L=%28P-2d%29%2F4%2B4d%2F4
L=%28P-2d%2B4d%29%2F4
highlight%28L=%28P%2B2d%29%2F4%29

Just substitute the values for d and P to get the values for w and L.