SOLUTION: tan θ = 1-cos2θ / sin2θ
Left Side
tan θ = sinθ/cosθ
Left Side = sinθ/cosθ
Right side
1-cos2θ/sin2θ
=1-(cos^2(θ
Algebra ->
Trigonometry-basics
-> SOLUTION: tan θ = 1-cos2θ / sin2θ
Left Side
tan θ = sinθ/cosθ
Left Side = sinθ/cosθ
Right side
1-cos2θ/sin2θ
=1-(cos^2(θ
Log On
Question 878332: tan θ = 1-cos2θ / sin2θ
Left Side
tan θ = sinθ/cosθ
Left Side = sinθ/cosθ
Right side
1-cos2θ/sin2θ
=1-(cos^2(θ)-sin^2(θ))/2sinθcosθ
This is where I get lost, any help in proving this identity would be great thanks.
The question in word format is; tan (theta) = One minus cos two theta over sin two theta
