SOLUTION: How do i try and work out a polynomial? The question i have gotten is which one of the following are polynomials? x^2+5x-4, (√x-3)(√x+3), √x^2+2x+1, 3x/4+1

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: How do i try and work out a polynomial? The question i have gotten is which one of the following are polynomials? x^2+5x-4, (√x-3)(√x+3), √x^2+2x+1, 3x/4+1      Log On


   



Question 878280: How do i try and work out a polynomial?
The question i have gotten is
which one of the following are polynomials?
x^2+5x-4, (√x-3)(√x+3), √x^2+2x+1, 3x/4+1, x^4-3x^2+6x-7, √x^2-2x
How would i simplify these to find out which one is the polynomial and if there is an easy method i could use.
Thank you

Answer by rothauserc(4718) About Me  (Show Source):
You can put this solution on YOUR website!
a polynomial can have
1) constants like 3, -20, 1/2
2) variables like x and y
3) exponents like the 2 in x^2 BUT only 0, 1, 2, 3, ..... are allowed
so, a polynomial can have constants, variables and exponents,
but never division by a variable.
A) x^2+5x-4 is a polynomial
B) (√x-3)(√x+3) = x - 9 is a polynomial
C) √x^2+2x+1 = x + 2x +1 = 3x + 1 is a polynomial and -x + 2x + 1 = x + 1 ia a polynomial
D) 3x/4+1 is a polynomial since division by a constant is allowed
E) x^4-3x^2+6x-7 is a polynomial
F) √x^2-2x = x - 2x = -x is a polynomial and -x -2x = -3x is a polynomial