SOLUTION: Horace Cope thought of three consecutive even integers and found that three times the sum of the first two was 58 less than 14 times the opposite of the third. what were his intege

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Question 878235: Horace Cope thought of three consecutive even integers and found that three times the sum of the first two was 58 less than 14 times the opposite of the third. what were his integers?
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
N-2,N,N%2B2
.
.
.
3%28N-2%2BN%29=14%28-%28N%2B2%29%29-58
3N-6%2B3N=-14N-28-58
6N-6=-14N-86
20N=80
N=4
Then,
N-2=2
N%2B2=6