SOLUTION: A survey found that an american family generates an average of 24lb of glass garbage each year. Assume that the standard deviation of the distribution is 4lb. If a sample of 49 49
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Question 878222: A survey found that an american family generates an average of 24lb of glass garbage each year. Assume that the standard deviation of the distribution is 4lb. If a sample of 49 49 families is selected find the probability that the sample mean is
a) below 15lb
B) above 26lb
You can put this solution on YOUR website! population: m = 24, sd = 4
Sample of 49
P(x < 15) = P(z< -9/(4/sqrt(49) = P(z < -9/.5714) = P(z < -15.75)basically zero chance
P(x > 26) = P(z > 2/.5714) = P(z > 3.50) = .0003
As You can see below,
z = 3.50 is way to the right and z = -15.75 is 'off the charts' way to the left.
Below: z = 0, z = ± 1, z= ±2 , z= ±3 are plotted along the Standard Normal Curve
Note: z = 0 (x value: the mean) 50% of the area under the curve is to the left and 50% to the right
