SOLUTION: name the direction vertex Axis of symmetry focus directrix of the parabola y= -1/4x^2

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Question 878129: name the direction vertex Axis of symmetry focus directrix of the parabola
y= -1/4x^2
Answer by lwsshak3(11628) About Me  (Show Source):
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name the direction vertex Axis of symmetry focus directrix of the parabola
y= -1/4x^2
x^2=-4y
This is an equation of a parabola that opens downward.
Its basic form of equation: (x-h)^2=-4p(y-k), (h,k)=coordinates of the vertex
vertex:(0,0)
axis of symmetry: x=0
4p=4
p=1
focus: (0,-1)
directrix: y=1