SOLUTION: solve the following: 4^(3x-2) = 22^x im some how certain this involves logs

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Question 877977: solve the following: 4^(3x-2) = 22^x
im some how certain this involves logs
Answer by josgarithmetic(39628) About Me  (Show Source):
You can put this solution on YOUR website!
4%5E%283x-2%29+=+22%5Ex

log%28%284%5E%283x-2%29%29%29=log%28%2822%5Ex%29%29
%283x-2%29log%28%284%29%29=x%2Alog%28%2822%29%29
3x%2Alog%28%284%29%29-2%2Alog%28%284%29%29=x%2Alog%28%2822%29%29
3x%2Alog%28%284%29%29-x%2Alog%28%2822%29%29=2%2Alog%28%284%29%29
x%283%2Alog%28%284%29%29-log%28%2822%29%29%29=2%2Alog%28%284%29%29

highlight%28x=%282%2Alog%28%284%29%29%29%2F%283%2Alog%28%284%29%29-log%28%2822%29%29%29%29
Decide what base you want and then compute.