SOLUTION: Why can't(-9+ sqrt(21))/6 be simplified further if all 3 numbers are multiples of three? Shouldn't you get "-3+7, which gives you 4 from dividing the numerator by 6? or at least 9+
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-> SOLUTION: Why can't(-9+ sqrt(21))/6 be simplified further if all 3 numbers are multiples of three? Shouldn't you get "-3+7, which gives you 4 from dividing the numerator by 6? or at least 9+
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Question 877951: Why can't(-9+ sqrt(21))/6 be simplified further if all 3 numbers are multiples of three? Shouldn't you get "-3+7, which gives you 4 from dividing the numerator by 6? or at least 9+ sqrt(7)/2? By the way the question is (3x+3)(x+2)=1 solve by quadratic formula. The help would be much obliged. Found 2 solutions by jim_thompson5910, josgarithmetic:Answer by jim_thompson5910(35256) (Show Source):
You can put this solution on YOUR website! The reason is because of that square root. If you had -9+21 over 6, then you can factor out 3. However, that 21 is buried in a root, so you can't factor out 3 from it.
I guess you could say this
but that's about it and it's not a good step in terms of simplifying
You can put this solution on YOUR website! (-9+ sqrt(21))/6 cannot be simplified because the terms of the numerator cannot be combined without approximation, and because all three separate numbers have no factors in common. Stated more plainly, -9 and sqrt(21) and 6 have no common factor.
Do not confuse the square root with the input of the square root. Seven is not a factor of .