SOLUTION: A. Solve log4 (3x-7)<2 B.Solve log9 (3x-7)>= log9 (2x+9) C. Evaluate (Log4 12^3) (log12 4^3)

Algebra ->  Trigonometry-basics -> SOLUTION: A. Solve log4 (3x-7)<2 B.Solve log9 (3x-7)>= log9 (2x+9) C. Evaluate (Log4 12^3) (log12 4^3)      Log On


   

Question 877918: A. Solve log4 (3x-7)<2
B.Solve log9 (3x-7)>= log9 (2x+9)
C. Evaluate (Log4 12^3) (log12 4^3)
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
A. Solve log4 (3x-7)<2
3x-7<16
3x<23
x<23/3
..
B.Solve log9 (3x-7)>= log9 (2x+9)
3x-7≥2x+9
x≥16
..
C. Evaluate (Log4 12^3) (log12 4^3)
log%284%2C%2812%5E3%29%29%2Alog%2812%2C%284%5E3%29%29
3log%284%2C%2812%29%29%2A3log%2812%2C%284%29%29
convert to base 4
3log%284%2C%2812%29%29%2A3log%284%2C%284%29%29%2Flog%284%2C%2812%29%29
3log%284%2C%2812%29%29%2A3%2Flog%284%2C%2812%29%29=3*3=9