SOLUTION: solve the following: 4^(3x-2) = 22^x
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Question 877683
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solve the following: 4^(3x-2) = 22^x
Answer by
lwsshak3(11628)
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solve the following: 4^(3x-2) = 22^x
(3x-2)log4=xlog22
(3x-2)/x=log22/log4≈2.2297
3x-2=2.2297x
0.7703x=2
x=2.5964