SOLUTION: Solve each equation 1. log7^4x = log7(3x+7)

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Question 877639: Solve each equation
1. log7^4x = log7(3x+7)
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
log%287%2C%284x%29%29=log%287%2C%283x%2B7%29%29


4x=3x%2B7 Since the logs have the same base, and are equal to one another, this means the arguments (the stuff inside) must be equal


4x-3x=7


x=7