SOLUTION: PLEASE HELP. A POINT MOVES SO THAT ITS DISTANCE FROM THE LINE {{{ x-16=0 }}} IS ALWAYS TWICE ITS DISTANCE FROM THE POINT (4, 0). DERIVE THE EQUATION OF ITS LOCUS.
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-> SOLUTION: PLEASE HELP. A POINT MOVES SO THAT ITS DISTANCE FROM THE LINE {{{ x-16=0 }}} IS ALWAYS TWICE ITS DISTANCE FROM THE POINT (4, 0). DERIVE THE EQUATION OF ITS LOCUS.
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Question 877535: PLEASE HELP. A POINT MOVES SO THAT ITS DISTANCE FROM THE LINE IS ALWAYS TWICE ITS DISTANCE FROM THE POINT (4, 0). DERIVE THE EQUATION OF ITS LOCUS. Answer by josgarithmetic(39618) (Show Source):
You can put this solution on YOUR website! Locus of points is the unknown (x, y).
The given line is x=16, so this is the variable point (16,y). The other given point is (4,0).
The description is that distance from (x,y) to (16,y) is two times the distance from (x,y) to (4,0). Transpose this into an equation using the Distance Formula and simplify.
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