SOLUTION: In a 2-car drag race , if both vehicles are going 200 mph and 1 vehicle crosses the finish line 1/10th of a sec before the other vehicle , what is the distance of victory ? Thank y

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Question 877362: In a 2-car drag race , if both vehicles are going 200 mph and 1 vehicle crosses the finish line 1/10th of a sec before the other vehicle , what is the distance of victory ? Thank you very much
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +d+ = the distance between them
when the one that is ahead crosses
the finish line
---------------
First convert +1%2F10+ sec to hrs
( sec ) x ( min / sec ) x ( hrs / min ) = hrs
+%28+1%2F10+%29%2A%28+1%2F60+%29%2A%28+1%2F60+%29+
+1%2F36000+ hrs
-----------------------------
For the car in second place:
+d+=+r%2At+
+d+=+200%2A%28+1%2F36000+%29+ mi
+d+=+2%2F360+
+d+=+1%2F180+ mi
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You can convert the miles to feet:
( mi ) x ( feet / mi ) = feet
+1%2F180+%29%2A5280+=+29.333+ ft
convert +.333+ ft to inches
+.333%2A12+=+4+
The distance of victory is 29 ft 4 in