SOLUTION: Please help me solve for x and y 4y+3y=50 and x^2+y^2=100

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Question 877287: Please help me solve for x and y
4y+3y=50 and x^2+y^2=100
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Please help me solve for x and y
4y+3y=50
x^2+y^2=100
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7y = 50
y = 50/7
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x^2 + (50/7)^2 = 100
x^2 = 100 - 2500/49 = 2400/49
x = 20sqrt(6)/7
x = -20sqrt(6)/7