SOLUTION: If logb x=0.36 and logb z=0.83
What does logb (square root of x)- logb (cube root of z)= ???
I need to understand how to perform this operation.
Thank you!
Question 877272: If logb x=0.36 and logb z=0.83
What does logb (square root of x)- logb (cube root of z)= ???
I need to understand how to perform this operation.
Thank you! Answer by nerdybill(7384) (Show Source):
You can put this solution on YOUR website! If logb x=0.36 and logb z=0.83
What does logb (square root of x)- logb (cube root of z)= ???
.
Strategy is to rewrite:
logb (square root of x)- logb (cube root of z)
in terms of what's given logb x and logb z:
rewrite original with exponents:
logb (x^(1/2))- logb (z^(1/3))
apply log rule to get:
(1/2)logb x - (1/3)logb z
substitute:
(1/2)(0.36) - (1/3)(0.83)
0.18 - 0.2767
-0.4567
