SOLUTION: Alcohol and water are mixed in the ratio of 1:4 by volume. Volume of the solution is 600 cm3, volume of alcohol is 120 cm3 and volume of water is 480 cm3. How much alcohol must b

Algebra ->  Percentage-and-ratio-word-problems -> SOLUTION: Alcohol and water are mixed in the ratio of 1:4 by volume. Volume of the solution is 600 cm3, volume of alcohol is 120 cm3 and volume of water is 480 cm3. How much alcohol must b      Log On


   



Question 877169: Alcohol and water are mixed in the ratio of 1:4 by volume. Volume of the solution is 600 cm3, volume of alcohol is 120 cm3 and volume of water is 480 cm3. How much alcohol must be added to the solution so that the ratio of alcohol to water in the solution becomes 1:3 by volume?
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Let x = amount of alcohol added


120/480 = 1/4


(120+x)/480 = 1/3


3(120+x) = 1*480


360+3x = 480


3x = 480-360


3x = 120


x = 120/3


x = 40


You need to add 40 cm^3 of alcohol.