SOLUTION: A rectangular poster covers an area of 2 square feet on a bulletin board. The width of the poster is 1 foot more than its length. Find the length and width of the poster, in fee

Algebra ->  Rectangles -> SOLUTION: A rectangular poster covers an area of 2 square feet on a bulletin board. The width of the poster is 1 foot more than its length. Find the length and width of the poster, in fee      Log On


   

Question 877168: A rectangular poster covers an area of 2 square feet on a bulletin board. The width of the poster is 1 foot more than its length.
Find the length and width of the poster, in feet.
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
x*(x+1) = 2

x^2 + x = 2

x^2 + x - 2 = 0

(x - 1)(x + 2) = 0

x - 1 = 0 or x + 2 = 0

x = 1 or x = -2

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Toss out the negative solution

The only solution is x = 1


Length: x = 1

Width: x+1 = 1+1 = 2