SOLUTION: How would I write the following expressions as complex numbers in standard form? -i(4 - 8i) (5 - 7i)(-4 - 3i) 6i/3 - i -2 - 5i/3i

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Question 877094: How would I write the following expressions as complex numbers in standard form?
-i(4 - 8i)
(5 - 7i)(-4 - 3i)
6i/3 - i
-2 - 5i/3i
Answer by harpazo(655) About Me  (Show Source):
You can put this solution on YOUR website!
The standard form looks like
a + bi.
Post one question at a time or else no one will reply.
I will do (5 - 7i)(-4 - 3i).
Use FOIL method to expand.
5(-4) = -20
5(3i) = 15i
(-7i)(-4) = -28i
(-7i)(-3i) = 21i^2
We have -20+15i-28i+21i^2.
Remember i^2 = -1
-20-13i+21(-1)
-20-13i-21
Answer: -41-13i