SOLUTION: The equation h=-16t^2+112t gives the height of an arrow, shot upward from the ground with an initial velocity of 112ft/s, where t is the time after the arrow leaves the ground. Fin

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: The equation h=-16t^2+112t gives the height of an arrow, shot upward from the ground with an initial velocity of 112ft/s, where t is the time after the arrow leaves the ground. Fin      Log On


   

Question 87708: The equation h=-16t^2+112t gives the height of an arrow, shot upward from the ground with an initial velocity of 112ft/s, where t is the time after the arrow leaves the ground. Find the time it takes for the arrow to reach a height of 180 ft.
Answer by tutorcecilia(2152) About Me  (Show Source):
You can put this solution on YOUR website!
h=-16t^2+112t
180=-16t^2+112t [Let (h) = 180]
0 = -16t^2+112t-180 [set the equation equal to zero]
Use the quadratic formula to factor
x=2.5 seconds ascending or x = 4.5 seconds descending