Question 877073: a number consists of two digits. The digits in the tenth place is 3 times the digit at unit place.If 54 is subtracted from number the digits are reversed then the number is ?
Answer by ankor@dixie-net.com(22740)   (Show Source):
You can put this solution on YOUR website! a number consists of two digits.
let a = 10's digit, let b = tens digit
then
10a + b = "the number"
:
The digits in the tenth place is 3 times the digit at unit place.
a = 3b
:
If 54 is subtracted from number the digits are reversed then the number is ?
10a + b - 54 = 10b + a
10a - a + b - 10b = 54
9a - 9b = 54
simplify, divide by 9
a - b = 6
replace a with 3b
3b - b = 6
2b = 6
b = 6/2
b = 3 is the units
I'll let you find the 10's digit, check your solutions in the 2nd statement
|
|
|
