SOLUTION: find three consecutive positive odd integers such that the product of the second and third integers is 18 more than 9 times the first integer

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Question 877064: find three consecutive positive odd integers such that the product of the second and third integers is 18 more than 9 times the first integer
Answer by nikhilsingh8898@gmail.com(1) About Me  (Show Source):
You can put this solution on YOUR website!
Let the consecutive odd positive integers be x,x+2,x+4.Then according to the question,
(x+2)(x+4)=18+9x
x^2+4x+2x+8=18+9x
x^2-3x-10=0
By spliting the middle term we get,
x^2-5x+2x-10=0
x(x-5)+2(x-5)=0
(x+2)(x-5)=0
So, x=-2 or x=5.but 2is negative so we take x=5
Putting the value of x we get,
x=5, x+2=7, x+4=9.
therefore,three consecutive odd positve integers are 5,7 and 9.