SOLUTION: Given that- (a^2-b^2)sinx+2abcosx=a^2+b^2. then find the value of tanx ?

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Question 877030: Given that-
(a^2-b^2)sinx+2abcosx=a^2+b^2.
then find the value of tanx ?
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
Given that-
%28a%5E2-b%5E2%29sinx%2B2abcosx=a%5E2%2Bb%5E2
then find the value of tanx ?
divide both sides by cosx:
%28a%5E2-b%5E2%29sinx%2Fcosx%2B2ab=%28a%5E2%2Bb%5E2%29%2Fcosx
%28a%5E2-b%5E2%29%28sinx%2Fcosx%29=-2ab%2B%28a%5E2%2Bb%5E2%29%2Fcosx
%28a%5E2-b%5E2%29%28sinx%2Fcosx%29=%28-2abcosx%2Ba%5E2%2Bb%5E2%29%2Fcosx
%28sinx%2Fcosx%29=%28-2abcosx%2Ba%5E2%2Bb%5E2%29%2F%28a%5E2-b%5E2%29cosx
tanx=%28-2abcosx%2Ba%5E2%2Bb%5E2%29%2F%28a%5E2-b%5E2%29cosx