SOLUTION: An airplane flies 1449 mi against the wind and 1539 mi with the wind in a total time of 5 hr. The speed of the airplane in still air is 600 mph. What is the speed of the wind?

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Question 876953: An airplane flies 1449 mi against the wind
and 1539 mi with the wind in a total time of 5 hr. The
speed of the airplane in still air is 600 mph. What is the speed of the wind?

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +w+ = the windspeed in mi/hr
+600+%2B+w+ = the speed of the plane
flying with the wind
+600+-+w+ = the speed if the wind
flying against the wind
------------------------
(1) +1449+=+%28+600+-+w+%29%2At%5B1%5D+
(2) +1539+=+%28+600+%2B+w+%29%2At%5B2%5D+
(3) +t%5B1%5D+%2B+t%5B2%5D+=+5+
----------------------------
There are 3 equations and 3 unknowns
so it's solvable
(1) +t%5B1%5D+=+1449+%2F+%28+600+-+w+%29+
(2) +t%5B2%5D+=+1539+%2F+%28+600+%2B+w+%29+
------------------------------
By substitution:
(3) +1449+%2F+%28+600+-+w+%29++%2B+1539+%2F+%28+600+%2B+w+%29+=+5+
Multiply both sides by +%28+600+-+w+%29%2A%28+600+%2B+w+%29+
(3) +1449%2A%28+600+%2B+w+%29+%2B+1539%2A%28+600+-+w+%29+=+5%2A%28+360000+-+w%5E2+%29+
(3) +869400+%2B+1449w+%2B+923400+-+1539w+=+1800000+-+5w%5E2+
(3) +5w%5E2+%2B+2988w+%2B+1792800+-+1800000+=+0+
(3) +5w%5E2+-+90w+-+7200+=+0+
(3) +w%5E2+-+18w+-+1440+=+0+
-----------------------------
I'll try completing the square:
(3) +w%5E2+-+18w+%2B+%28+18%2F2+%29%5E2+=+1440+%2B+%28+18%2F2+%29%5E2+
(3) +w%5E2+-+18w+%2B+81+=+1440+%2B+81+
(3) +%28+w+-+9+%29%5E2+=+1521+
(3) +%28+w+-+9+%29%5E2+=+39%5E2+
Take the square root of both sides
(3) +w+-+9+=+39+
(3) +w+=+48+
The windspeed is 48 mi/hr
-------------------------
check:
(1) +1449+=+%28+600+-+48+%29%2At%5B1%5D+
(1) +t%5B1%5D+=+1449+%2F+552+
(1) +t%5B1%5D+=+2.625+
and
(2) +t%5B2%5D+=+1539+%2F+%28+600+%2B+48+%29+
(2) +t%5B2%5D+=+1539+%2F+648+
(2) +t%5B2%5D+=+2.375+
and
(3) +t%5B1%5D+%2B+t%5B2%5D+=+5+
(3) +2.625+%2B+2.375+=+5+
(3) +5+=+5+
OK