SOLUTION: find two consecutive integers such that 3 times the first integer is 27 less than 6 times the second.
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Question 876818
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find two consecutive integers such that 3 times the first integer is 27 less than 6 times the second.
Answer by
CubeyThePenguin(3113)
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consecutive integers: x, (x+1)
3x = 6(x+1) - 27
3x = 6x-21
-3x = -21
x = 7
The integers are 7 and 8.
