SOLUTION: What are the points of discontinuity? Y=x-2/x^2+5x-6

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Question 876722: What are the points of discontinuity?
Y=x-2/x^2+5x-6
Found 2 solutions by Alan3354, edjones:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Where the DEN = 0
Find x such that x%5E2+%2B+5x+-+6+=+0

Answer by edjones(8007) About Me  (Show Source):
You can put this solution on YOUR website!
The zeroes of the numerator and and undefined points in the denominator are the points of discontinuity.
.
x^2+5x-6=(x+6)(x-1)
x= -6 and x= 1 are undefined points in the denominator.
.
graph%28300%2C300%2C-10%2C10%2C-10%2C10%2C%28%28x-2%29%2F%28x%5E2%2B5x-6%29%29%29
Ed