SOLUTION: What is the largest of 3 consecutive positive even integers such that the product of the first and second is 8 less than 11 times the third?

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Question 876700: What is the largest of 3 consecutive positive even integers such that the product of the first and second is 8 less than 11 times the third?
Answer by LinnW(1048) About Me  (Show Source):
You can put this solution on YOUR website!
x = the first number
x + 1 = the second number
x + 2 = the third number
(x)*(x + 1) = 11*(x + 2) - 8
x^2 + x = 11x + 22 -8
x^2 + x = 11x + 14
subtract 11x from each side
x^2 -10x = 14
add -14 to each side
x^2 -10x -14 = 0
There is no integer solution.