SOLUTION: How do you write 4x^2-y^2-16x-4y-4=0 in standard form

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Question 876615: How do you write 4x^2-y^2-16x-4y-4=0 in standard form
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
4x^2-y^2-16x-4y-4=0
4x^2-y^2-16x-4y=4
4(x-2)^2 -(y+12)^2 = 4 +16 -4 = 16
4(x-2)^2 -(y+12)^2 = 16
(x-2)^2/4 -(y+12)^2/16 = 1